Taperssection.com
Gear / Technical Help => Ask The Tapers => Topic started by: Sean Gallemore on July 02, 2004, 03:38:50 AM
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a certain microphone I wanna get has this to say:
Supply voltage: 5-50 Vdc supplied via a resistor value equivalent to: R=2(V-2.5) kOhm
I'm not an EE major so I was wondering what the numbers at the end mean.
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ok, armen clued me in that the stuff on the end is an equation (duh, + armen) so that means I need a 91 kilo-Ohm resistor for 48V phantom power. Does this sound right?
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ok, armen clued me in that the stuff on the end is an equation (duh, + armen) so that means I need a 91 kilo-Ohm resistor for 48V phantom power. Does this sound right?
No! Ask DPA what they actually mean!
Jon
done and done
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Schwillaby,
I might have been to quick in my prior reply. I took "48 Volts" to mean a standard phantom power
scheme with 6k8 drop resistors already in place.
But if you build a power scheme for the DPA 406x from scratch I believe the formula you arrived at
is correct and identical to that provided by DPA for these mics.
Jon
ok, thank you for that, Jon
Javi in another thread posted this
so all of these adapters regulate power down to 7V. what about the battery boxes? Yeah they take a 9V battery but they can be dropped to 7V as well, no? Could I use my Sound Pro battery box for this? Just asking....
the HEB box (made by coresound for the DPA406xs) in fact uses 9V and just a resistor + a capacitor for each channel (without dropping to 7V).
Getting the sound pro battery box to work with the DPAs could be as easy as replacing the resistors with 10K ohm values (that's what HEB boxes use) and the capacitors will also probably need to be replaced with other values as well if you want to use the rolloff.
I would be down for replacing resistors. I'm not overly concerned with bass-roll-off. If I need it, I have it on the MP-2