I've been looking at my PS-2 with a view to re-wiring it to a single miniplug. Looking at the PCB, I think my soldering skills would probably not be up to the job, so I'm thinking about just chopping off the XLRs and wiring the existing cable to a miniplug.
When I looked inside the 2nd XLR (the one that sort of piggy-backs out of the other) the pins were connected like this:
1: black
2: red & blue
3: clear & black
Given that the PCB allocation is given above as...
RIGHT CHANNEL
red wire +
clear wire -
shield is the ground
LEFT CHAN
blue wire +
black wire -
ground.
...please could someone explain to me what is happening here. It seems to my decidedly un-electronic mind that the + and - from both channels are wired to the same plug, which doesn't really make sense to me.
Also could someone give me an idiot's guide to wiring the miniplug? Something along the lines of "blue to tip, red to ring, grounds to sleeve, leave everything else unconnected" - which is what sounds obvious to me.
Thanks is advance.
EDIT: looking more closely at the other plug, it looks like they've just coupled lengths of the unused wires (the blue and the black) to make an extra connections for pins 2 & 3. For added security or just so that there weren't unconnected wires left trailing?