okay, so this sucker finally ran out... It got about 50 hours on a 7.5ah batt. So if my calculations are correct:
Battery mAh (7.5) times current draw (x) times .80 = run time (50)
So that would make x=8.3... So the JB3 current draw is 8.3 according to my calculations. Does this sound right? I hope I did it right!
Not quite. Your initial equation is wrong: should divide battery mAH by current draw, not multiply. And 7.5 is the batt capacity in AH, not mAH - should be 7500 mAH:
( battery capacity / current draw ) * .80 = estimated run-time
( 7500 mAH / X ) * .80 = 50 hrs
( 7500 mAH ) * .80 = 50 hrs * X
( 7500 mAH * .80 ) / 50 hrs = X
X = 120 mA current draw
Even taking out the .80 fudge factor since the low current draw improves efficiency we're still only talking 150 mA draw. Seems
awfully low. Hmmmmm...what's going on here...can the NJB3 really draw so little current while recording?!?
Alex, did you run a digital signal into the NJB3 this whole time?
Also looks like you got pretty darn close to the theoretical max record space, ~30 hrs - any artifacts in the recordings?