The following details refer to a closed traverse.
Line 
Consecutive coordinate 

Northing(m) 
Southing(m) 
Easting(m) 
Westing(m) 

PQ 
 
437 
173 
 
QR 
101 
 
558 
 
RS 
419 
 
 
96 
SP 
 
83 
 
634 
The length and direction (as whole circle bearing) of closure, respectively are
∑Northing = 101 + 419 = 520 m
∑Southing = 437 + 83 = 520
∑Easting = 173 + 558 = 731 m
∑Westing = 96 + 634 = 730 m
∑L = ∑Northing  ∑Southing = 520 – 520 = 0
∑D = ∑Easting  ∑Westing = 731 – 730 = 1 m
\(\therefore {\rm{Length\;of\;closure}} = \sqrt {{{\left( {\sum {\rm{L}}} \right)}^2} + {{\left( {\sum {\rm{D}}} \right)}^2}} = \sqrt {{{\left( 0 \right)}^2} + {{\left( 1 \right)}^2}} = 1{\rm{\;m}}\)
\(\rm{{\rm{Direction\;of\;closure}},{\rm{\;\theta }} = {\tan ^{  1}}\left( {\frac{{\sum {\rm{D}}}}{{\sum {\rm{L}}}}} \right) = {\tan ^{  1}}\left( {\frac{1}{0}} \right) = 90^\circ }\)