whoa, lost me on that math. 20xlog? Looks like I'll stick to estimating...
Pretty sure that was sarcasm...
Use your ears - mix to taste...no magic formulas here.
no sarcasm here, Joe was just doing the math, based on the definition of the dB scale.
(though perhaps there was some confusion with the "x" "20xlog(1.5)" just means "20 times the log of 1.5".
L
dB = 20 x log(A
1/A
0)
in this case, A
1 and A
0 represent the amplitude of the two wav files. the Amplitude is a measure of how loud the sound is. So if you want a ratio of 60%/40%, the source that makes up 60% of the end result needs to be 1.5 times louder than the other source. that's just simple division. But to convert that to the decibal scale, you use the equation referenced above, and, as Joe calculated, the result is that source 1 needs to be 3.52dB louder than source 2 for a 60/40 mix. And, as a check, this makes logical sense in relation to what we'd expect, because a 6dB increase in volume means that the sound is twice as loud (and that's actually 6.02dB, if you do the math
). that's fairly common knowledge (or should be around here). And now we know that a 3.52dB increase in volume represents a factor of 1.5x increase in volume.
edit to add:
I agree with Joe, I remain skeptical that most people do the math. as Roving Sign says, just mix it until it sounds good to you